[3cos(2x)]-1=0

Solution for [3cos(2x)]-1=0 equation:

Simplifying
[3cos(2x)] + -1 = 0

Remove parenthesis around (2x)
[3cos * 2x] + -1 = 0

Reorder the terms for easier multiplication:
[3 * 2cos * x] + -1 = 0

Multiply 3 * 2
[6cos * x] + -1 = 0

Multiply cos * x
[6cosx] + -1 = 0

Reorder the terms:
-1 + [6cosx] = 0

Solving
-1 + [6cosx] = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + [6cosx] = 0 + 1

Combine like terms: -1 + 1 = 0
0 + [6cosx] = 0 + 1
[6cosx] = 0 + 1

Combine like terms: 0 + 1 = 1
[6cosx] = 1

Divide each side by '[6osx]'.
c = 0.1666666667o-1s-1x-1

Simplifying
c = 0.1666666667o-1s-1x-1